PaulEngr wrote:
Based on your description you're getting to 2 seconds...effectively the overcurrent protection is not operating at all and could be deleted from the circuit. When you are operating in "definite time" (2 seconds in this case), incident energy will increase with current. When you are operating within the inverse time region of an overcurrent protection device it can go either way. Most of the time incident energy goes down as current increases due to the fact that opening time decreases at a faster rate than the increase in arc power.
I'm less familiar with ETAP but with SKM it has a way of doing a partial update so that rather than solving the entire system with all buses you can manually select just a portion of the overall system and update that portion. Over time it slowly somehow gets corrupted doing this so when doing a lot of "what-if" scenario's after a few rounds of this it becomes necessary to do a fresh complete run.
I did some digging around in their "Help" section last night and based on other PE's suggestions on parallel feeding a bus, I've come to this:
1. ETAP, by default, will choose the longest pickup time for a protective device when there are multiple feeds into a bus. With the generator seeing about 2kA and the utility feed being around 24kA, the fault current is so low (as you've mentioned) that it's not tripping and going 120 cycles. Which brings me to my second conclusion.
2. In reality, the situation in which the emergency generator and the utility are both feeding the same bus occurs so infrequently, and additionally that live work would happen during that time, has led me to simply ignore this scenario while still informing the client of this particular scenario. The majority of the time the bus will be fed from the utility, followed by a blackout scenario where the emergency generator feeds the bus.
Thank you for your help!